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C 语言实例 - 计算两个时间段的差值
C 语言实例计算两个时间段的差值。
实例
#include <stdio.h>
struct TIME
{
int seconds;
int minutes;
int hours;
};
void differenceBetweenTimePeriod(struct TIME t1, struct TIME t2, struct TIME *diff);
int main()
{
struct TIME startTime, stopTime, diff;
printf("输入开始时间: \n");
printf("输入小时、分钟、秒：");
scanf("%d %d %d", &startTime.hours, &startTime.minutes, &startTime.seconds);
printf("输入停止时间: \n");
printf("输入小时、分钟、秒: ");
scanf("%d %d %d", &stopTime.hours, &stopTime.minutes, &stopTime.seconds);
// 计算差值
differenceBetweenTimePeriod(startTime, stopTime, &diff);
printf("\n差值: %d:%d:%d - ", startTime.hours, startTime.minutes, startTime.seconds);
printf("%d:%d:%d ", stopTime.hours, stopTime.minutes, stopTime.seconds);
printf("= %d:%d:%d\n", diff.hours, diff.minutes, diff.seconds);
return 0;
}
void differenceBetweenTimePeriod(struct TIME start, struct TIME stop, struct TIME *diff)
{
if(stop.seconds > start.seconds){
--start.minutes;
start.seconds += 60;
}
diff->seconds = start.seconds - stop.seconds;
if(stop.minutes > start.minutes){
--start.hours;
start.minutes += 60;
}
diff->minutes = start.minutes - stop.minutes;
diff->hours = start.hours - stop.hours;
}
输出结果为：
输入开始时间: 输入小时、分钟、秒：12 34 55 输入停止时间: 输入小时、分钟、秒: 8 12 5 差值: 12:34:55 - 8:12:5 = 4:22:50